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mx^(2) -bx +k = 0 Find time after whic...

`mx^(2) -bx +k = 0`
Find time after which of the energy will be come half of initial maximum value in damped forced oscillation .

A

`t = m/b +1/2 ln2`

B

`t = m/b xx 2/3 ln2`

C

`t = m/2 - 1/2 ln2`

D

`t = m/b xx 1/2 ln 2`

Text Solution

Verified by Experts

The correct Answer is:
D
`1/(sqrt(2)) = e^(-bt//m)`
`lnsqrt(2) = (bt)/(m)`
`t = m/b xx 1/2 ln2`
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