Assertion : A charge particle is released particle is released from rest in magnetic field then it will move in circular path.
Reason : Work done by magnetic field is non zero.

Answer

To solve the given question, we will analyze both the assertion and the reason step by step.

### Step 1: Understanding the Assertion
**Assertion:** A charged particle is released from rest in a magnetic field; then it will move in a circular path.

- When a charged particle is placed in a magnetic field and is at rest, it does not experience any magnetic force because the magnetic force depends on the velocity of the charge. The formula for the magnetic force is given by \( F = q(\mathbf{v} \times \mathbf{B}) \), where \( q \) is the charge, \( \mathbf{v} \) is the velocity, and \( \mathbf{B} \) is the magnetic field. Since the particle is at rest, \( \mathbf{v} = 0 \), and thus the magnetic force \( F = 0 \).

### Step 2: Conclusion from the Assertion
- Since the magnetic force is zero, the charged particle will not move in a circular path. Instead, it will remain at rest until acted upon by another force. Therefore, the assertion is **false**.

### Step 3: Understanding the Reason
**Reason:** Work done by the magnetic field is non-zero.

- The work done by a force is calculated using the formula \( W = F \cdot d \), where \( F \) is the force and \( d \) is the displacement. In the case of a magnetic field, if the magnetic force is zero (as established above), then the work done by the magnetic field will also be zero.

### Step 4: Conclusion from the Reason
- Since the magnetic force is zero, the work done by the magnetic field is also zero. Therefore, the reason is **false**.

### Final Conclusion
- Both the assertion and the reason are false. Thus, the correct option is **Option 4: Assertion and reason are both false**.

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