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I10=int0^(pi/2)x^(10)sinx dx then I10+90...

`I_10=int_0^(pi/2)x^(10)sinx dx` then `I_10+90I_8` is (A) `10(pi/2)^6` (B) `10(pi/2)^9` (C) `10(pi/2)^8` (D) `10(pi/2)^7`

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If I_n=int_0^(pi/2) x^n sinx dx , then [I_4+12I_2] is equal to (A) 4pi (B) 3(pi/2)^3 (C) (pi/2)^2 (D) 4(pi/2)^3