यदि `cos theta = (p-1)/(p+1)`,तब `1/(tan theta)`के मान ज्ञात कीजिए ।

Explanation

हम एक समकोण `Delta ABC`खींचते है जिसमें
`angleB = 90^(@), BC = p - 1 " तथा " AC = p +1`.
अब ,`cos angleABC = (BC)/(AC) = (p-1)/(p+1)`
प्रश्न से ,`cos theta = (p-1)/(p+1)`
` :. cos angleACB = cos theta " " :. angleACB = theta `
समकोण `DeltaABC` में ,
` AB = sqrt(h^(2) - b^(2)) = sqrt((p+1)^(2) - (p-1)^(2)) = sqrt((p+1+p-1)(p+1-p+1))`
` = sqrt((2p)*2) = sqrt(4p) = 2 sqrtp`
` :. tan theta = p/b = (AB)/(BC) = (2sqrtp)/(p-1)" ":. 1/(tan theta) = (p-1)/(2sqrtp)`