यदि `pi = 180^(@)`,तब निम्नलिखित का मान ज्ञात करें ।
` sin^(2). pi/3 + tan^(2) . pi/6 - cos^(2) . pi/2`

Explanation

`sin^(2) .pi/3+ tan^(2) . pi/6 - cos^(2). pi/2 = sin^(2). (180^(@))/3 + tan^(2) . (180^(@))/6 - cos^(2). (180^(@))/2`
` = sin^(2) 60^(@) + tan^(2) 30^(@) - cos^(2) 90^(@)`
` = (sqrt3/2)^(2) + (1/sqrt3)^(2) - (0)^(2) = 3/4 + 1/3 - 0 = (9+4)/12 = 13/12`.