लिखित उत्तर
Verified by Experts
NOOTAN HINDI-प्रतिलोम त्रिकोणमितीय फलन -विविध प्रश्नावली
- tan^(-1)""(1)/(2)+tan^(-1)""(1)/(3)
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- cos^(-1)(cos""(13pi)/(6))
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- tan^(-1)(tan""(7pi)/(6))
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- 2sin^(-1)""(3)/(5)=tan^(-1)""(24)/(7)
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- sin^(-1)""(8)/(17)+sin^(-1)""(3)/(4)=tan^(-1)""(77)/(36)
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- cos^(-1)""(4)/(5)+cos^(-1)""(12)/(13)=cos^(-1)""(33)/(65)
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- cos^(1)""(12)/(13)+sin^(-1)""(3)/(5)=sin^(-1)""(56)/(65)
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- tan^(-1)""(63)/(16)=sin^(-1)""(5)/(13)+cos^(-1)""(3)/(5)
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- tan^(-1)""(1)/(5)+tan^(-1)""(1)/(7)+tan^(-1)""(1)/(3)+tan^(-1)""(1)/(8...
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- tan^(-1)sqrtx=(1)/(2)cos^(-1)((1-x)/(1+x)),x""in[0,1]
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- cos^(-1)((sqrt(1+sinx)+sqrt(1-sinx))/(sqrt(1+sinx)-sqrt(1-sinx)))=(x)/...
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- tan^(-1)((sqrt(1+x)-sqrt(1-x))/(sqrt(1+x)+sqrt(1-x)))=(pi)/(4)-(1)/(2)...
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- (9pi)/(8)-(9)/(4)sin^(-1)""(1)/(3)=(9)/(4)sin^(-1)""(2sqrt2)/(3)
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- 2tan^(-1)(cosx)=tan^(-1)(2cosecx)
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- tan^(-1)""(1-x)/(1+x)=(1)/(2)tan^(-1)x,(xgt0)
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- sin(tan^(-1)x),|x|lt1 बराबर होता है :
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- यदि sin^(-1)(1-x)-2sin^(-1)x=(pi)/(2) तो x का मान बराबर है :
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- tan^(-1)((x)/(y))-tan^(-1)""(x-y)/(x+y) का मान है :
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