An ac source is connected across a resistance of `10 Omega` The power dissipated in the resistor is `100W` The rms valuse of the current and voltge are .

An ac source is connected in series with an inductor of 5H and a resistor of 1000Omega . The rms value of voltage of the source is 100 V and the frequency of the source is 50cps. What is the rms value of the current in the circuit? What is the phase difference of the voltage and the current in the circuit? What is the power dissipated in the circuit?

When a battery connected across a resistor of 16 Omega , the voltage across the resistor is 12 V. When the same battery is connected across a resistor of 10 Omega , voltage across it is 11 V. The internal resistance of the battery (in ohm) is

When a battery connected across a resistor of 16 Omega , the voltage across the resistor is 12 V. When the same battery is connected across a resistor of 10 Omega , voltage across it is 11 V. The internal resistance of the battery (in ohm) is

An AC supply gives 30 underset(rms)(V) which passes 10 Omega resistance. The power dissipated in it is

Find the power dissipated in 3 Omega resistance of the network of resistors.

A dc source of 30 V is connected across 2 resistores of 200 Omega each connected in series. A voltmeter of resistance 200 Omega is connected across a resistor. It reads

An AC supply gives 30 V_rms which passes through a 10 Omega resistance. The power dissipated in it is