One gm mol of a diatomic gas `(gamma=1.4)` is compressed adiabatically so that its temperature rises from `27^(@)C` to `127^(@)C` . The work done will be

One gm mol of a diatomic gas (gamma=1.4) is compressed adiabatically so that its temper ature rises from 27^(@)C to 127^(@)C . The work done will be

A mass of diatomic gas (gamma=1.4) at a pressure of 2 atomphere is compressed adiabitically so that its temperature rises from 27^(@)C to 927^(@)C . The pressure of the gas in the final state is

A mass of diatomic gas (gamma=1.4) at a pressure of 2 atomphere is compressed adiabitically so that its temperature rises from 27^(@)C to 927^(@)C . The pressure of the gas in the final state is

One mole of an ideal gas (gamma=7//5) is adiabatically compressed so that its temperature rises from 27^(@)C to 35^(@)C the work done by the gas is (R=8.47J/mol-K)

One mole of an ideal gas (gamma=1.4) is compressed adiabatically , so that its temperature is increased from 27^@ C " to " 35^@C If R = 8.31 J/K/mole then the change in the internal energy of the gas is :

One mole of an ideal gas with gamma=1.4 is adiabatically compressed so that its temperature rises from 27^(@)C to 34^(@)C . The change in the internal energy of the gas is (R=8.3J mol^(-10k^(-1)))

A cylinder containing one gram molecule of the gas was compressed adiabaticaly untill its tempertaure rose from 27^(@)C to 97^(@)C . Calculate the work done and heat produced in the gas (gamma=1.5) .