The cross-section of a bar is given by `[1 + (x^(2))/(100)]cm^(2)`, where `'x'` is the distance from one end. If the extension under a load of `'20 kN'` on a length of `10 cm` is `lambda xx 10^(-3) cm` then find `lambda`.
`Y = 2 xx 10^(5)N//mm^(2)`.

A load of 100 N acts on a bar of length 10 cm and area of cross section 1 cm. Find the energy stored in it. (Y= 10^(11) N//m^(2))

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

The area of cross section of a steel wire (Y=2.0 xx 10^(11) N//m^(2)) is 0.1 cm^(2) . The force required to double is length will be

A steel rod of length 50 cm has a cross–sectional area of 0.4 cm^(2) . What force would be required to stretch this rod by the same amount as the expansion produced by heating it through 10^(@)C . ( alpha = 10^(-5) k^(-1) and Y = 2 xx 10^(11) N//m^(2))

A brass of length 2 m and cross-sectional area 2.0 cm^(2) is attached end to end to a steel rod of length and cross-sectional area 1.0 cm^(2) . The compound rod is subjected to equal and oppsite pulls of magnitude 5 xx 10^(4) N at its ends. If the elongations of the two rods are equal, the length of the steel rod (L) is { Y_(Brass) = 1.0 xx 10^(11) N//m^(2) and Y_(steel) = 2.0 xx 10^(11) N//m^(2)

A brass of length 2 m and cross-sectional area 2.0 cm^(2) is attached end to end to a steel rod of length and cross-sectional area 1.0 cm^(2) . The compound rod is subjected to equal and oppsite pulls of magnitude 5 xx 10^(4) N at its ends. If the elongations of the two rods are equal, the length of the steel rod (L) is { Y_(Brass) = 1.0 xx 10^(11) N//m^(2) and Y_(steel) = 2.0 xx 10^(11) N//m^(2)