If velocity of a particle is given by `v= (2t+3) m//s` then average velocity in interval `0 le t le 1`s is :

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

Velocity of a particle is given by v = (3t ^(2) +2t) m/s. Find its average velocity between t = 0 to t=3s and also find its acceleration at t = 3s. Motion of the particle is in one dimension.

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

. If the velocity of a particle is (10 + 2 t 2) m/s , then the average acceleration of the particle between 2s and 5s is

The position of a particle moving on the x-axis is given by x=t^(3)+4t^(2)-2t+5 where x is in meter and t is in seconds (i) the velocity of the particle at t=4 s is 78 m//s (ii) the acceleration of the particle at t=4 s is 32 m//s^(2) (iii) the average velocity during the interval t=0 to t=4 s is 30 m//s (iv) the average acceleration during the interval t=0 to t=4 s is 20 m//s^(2)

If the velocity of a particle is (10+2t^(2)m/s ,then the average acceleration of the particle between 2s and 5s is (in m/s^2)

The position of a particle is given by the function s(t)= 2 t^2 + 3t - 4. Find the time t=c in the interval 0 le t le 4 when the instantaneous velocity of the particle equals to its average velocity in this interval.