If `alpha, beta` be the roots of the equation `x^2-px+q=0` then find the equation whose roots are `q/(p-alpha)` and `q/(p-beta)`

Explanation

Let `q/(p-alpha)=ximplies=p-q/x`
So we replacing `x` by `p-q/x` in the given equation we get
`(p-q/x)^(2)-p(p-q/x)+q=0`
`impliesp^(2)+(q^(2))/(x^(2))-(2pq)/x-p^(2)+(pq)/x+q=0`
`impliesq-(pq)/x+(q^(2))/(x^(2))=0`
or `qx^(2)-pqx+q^(2)=0` or `x^(2)-px+q=0`
is the required equation whose roots are `q/(p-alpha)` and `q/(p -beta)`