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[1/4]+[1/4+1/200]+[1/4+1/100]+.....[1/4+...

`[1/4]+[1/4+1/200]+[1/4+1/100]+.....[1/4+199/200]` is

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The give expression can be written as
`[1/4]+[1/4+1/200]+[1/4+2/200]+[1/4+3/200]`
`+….+[1/4+199/200]`
`=[200.1/4]=[50]=50` [from property (xiv)]
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Find the value of [3/4]+[3/4+1/100]+[3/4+2/100]+...+[3/4+99/100] .

If [x] denotes the integral part of x for real x, and S= [(1)/(4)]+[(1)/(4) +(1)/(200)]+[(1)/(4)+(1)/(100)] + [(1)/(4)+(3)/(200)] .....+ [(1)/(4)+ (199)/(200)] then S is

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If A = [(2,2,1), (1,3,1), (1,2,2)] then A^-1+(A-5I) (AI)^2 = (i) 1/ 5 [[4,2, -1], [-1,3,1], [-1,2,4]] (ii) 1/5 [[4, -2, -1], [-1, 3, -1], [-1, -2,4]] (iii) 1/3 [[4,2, -1], [-1,3,1], [-1,2,4]] (iv) 1/3 [[4, -2, -1], [-1,3, -1], [-1, -2,4]]

ARIHANT MATHS-THEORY OF EQUATIONS-Exercise (Questions Asked In Previous 13 Years Exam)
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