Solve the equation `sqrt((6-x))(3^(x^(2)-7.2x+3.9)-9sqrt(3))=0`

Explanation

We have
`sqrt((6-x))(3^(x^(2)-7.2x+3.9)-9sqrt(3))=0`
This equation is defined for
`6-xge0`. i.e. `xle6` …….i
This equation is equivalent to the collection of equations
`sqrt(6-x)=0` and `3^(x^(2)-7.2x+3.9)-9sqrt(3)=0`
`:.x_(1)=6` and `3^(x^(2)-7.2x+3.9)=3^(2.5)`
Then `x^(2)-7.2x+3.9=2.5`
`x^(2)-7.2x+1.4=0`
We find that `x_(2)=1/5` and `x_(3)=7`
Hence solution of the original equation are [which satisfies Eq.(i) ]
`x_(1)=6,x_(2)=1/5`