If one root of the quadratic equation `ix^2-2(i+1)x +(2-i)=0,i =sqrt(-1)` is `2-i`, the other root is

Options

A. `3+i`
B. `3+sqrt(-1)`
C. `-1+i`
D. `-1-i`

Answer

D

Explanation

Since all the coefficients of given equation are not real.
Therefore, other root `!=3+i`
Let other root be `alpha`.
Then sum of the roots`=(2(1+i))/i`
`impliesalpha+3-i=(2(1+i))/i`
`impliesalpha+3-i=2-2i`
`:.alpha=-1-i`