Home
Class 12
MATHS
Statement-1 If U is universal set and B ...

Statement-1 If U is universal set and B = U - A, then n(B) = n(U) - n(A).
Statement-2 For any three arbitrary sets A, B and C, if C = A - B, then n(C ) = n(A) - n(B).

Text Solution

Verified by Experts

The correct Answer is:
c

`because B = U - A = A'`
`therefore n(B) = n(A') = n(U) - n(A)`
So, Statement-1 is true.
But for any three arbitrary sets A, B and C, we cannot always have
n(C ) = n(A) - n(B)
if C = A - B
As it is not specified A is universal set not. In case not conclude.
n(C ) = n(A) - n(B)
Hence, Statement-2 is false.
Promotional Banner

Topper's Solved these Questions

  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 1|11 Videos
  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 2|10 Videos
  • SEQUENCES AND SERIES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|38 Videos
  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|18 Videos

Similar Questions

Explore conceptually related problems

Let U be the universal set and A uu B uu C = U . Then {(A - B) uu (B- C) uu (C-A)} is equal to -

Let U be the universal set and A cup B cup C=U "Then" [ (A-B) cup (B-C) cup (C-A)] equals

If A;B and C are finite sets and U be the universal set then n(A-B)=n(A)-n(A nn B)

Statement 1 is True: Statement 2 is True; Statement 2 is a correct explanation for statement 1 Statement 1 is true, Statement 2 is true;2 Statement 2 not a correct explanation for statement 1. Statement 1 is true, statement 2 is false Statement 1 is false, statement 2 is true Statement I: If A is obtuse angle I A B C , then tanB\ t a n C<1 because Statement II: In A B C ,\ t a n A=(t a n B+t a n C)/(t a n B t a n C-1)\ a. A b. \ B c. \ C d. D

Given n(U) = 20, n(A) = 12, n(B) = 9, n(AnnB) = 4, where U is the universal set, A and B are subsets of U, then n((AuuB)') equals

If A;B and C are finite sets and U be the universal set then n(A Delta B)=n(A)+n(B)-2n(A nn B)