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If two sets A and B are having 99 elemen...

If two sets A and B are having 99 elements in common, the number of elements common to each of the sets `A xx B` and `B xx A` are `121 lambda^(2)`, the value of `lambda` is

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To solve the problem, we need to find the value of \( \lambda \) given that the number of elements common to the Cartesian products \( A \times B \) and \( B \times A \) is \( 121 \lambda^2 \) and that the two sets \( A \) and \( B \) have 99 elements in common. ### Step-by-Step Solution: 1. **Identify the Given Information**: - The number of elements in the intersection of sets \( A \) and \( B \) is \( |A \cap B| = 99 \). - The number of elements common to \( A \times B \) and \( B \times A \) is given as \( 121 \lambda^2 \). 2. **Understanding Cartesian Products**: - The Cartesian product \( A \times B \) consists of ordered pairs \( (a, b) \) where \( a \in A \) and \( b \in B \). - The number of elements in \( A \times B \) is given by \( |A| \times |B| \). - Similarly, the number of elements in \( B \times A \) is \( |B| \times |A| \). 3. **Common Elements in Cartesian Products**: - The common elements in \( A \times B \) and \( B \times A \) are those pairs where the first element is from \( A \cap B \) and the second element is also from \( A \cap B \). - Therefore, the number of common elements is given by \( |A \cap B| \times |A \cap B| = |A \cap B|^2 \). 4. **Setting Up the Equation**: - From the above, we have: \[ |A \cap B|^2 = 99^2 \] - We also know that: \[ |A \cap B|^2 = 121 \lambda^2 \] - Setting these equal gives: \[ 99^2 = 121 \lambda^2 \] 5. **Calculating \( 99^2 \)**: - Calculate \( 99^2 \): \[ 99^2 = 9801 \] 6. **Substituting into the Equation**: - Substitute \( 9801 \) into the equation: \[ 9801 = 121 \lambda^2 \] 7. **Solving for \( \lambda^2 \)**: - Divide both sides by 121: \[ \lambda^2 = \frac{9801}{121} \] 8. **Calculating \( \frac{9801}{121} \)**: - Calculate \( \frac{9801}{121} \): \[ \frac{9801}{121} = 81 \] 9. **Finding \( \lambda \)**: - Taking the square root of both sides gives: \[ \lambda = \sqrt{81} = 9 \] ### Final Answer: Thus, the value of \( \lambda \) is \( 9 \).

To solve the problem, we need to find the value of \( \lambda \) given that the number of elements common to the Cartesian products \( A \times B \) and \( B \times A \) is \( 121 \lambda^2 \) and that the two sets \( A \) and \( B \) have 99 elements in common. ### Step-by-Step Solution: 1. **Identify the Given Information**: - The number of elements in the intersection of sets \( A \) and \( B \) is \( |A \cap B| = 99 \). - The number of elements common to \( A \times B \) and \( B \times A \) is given as \( 121 \lambda^2 \). ...
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