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If ABCD is a parallelogram and the posit...

If ABCD is a parallelogram and the position vectors of A,B and C are `hati+3hatj+5hatk, hati+hatj+hatk and 7 hati+7hatj+7hatk`, then the poisition vector of D will be

A

`7hati+5hatj+3hatk`

B

`7hati+9hatj+11hatk`

C

`9hati+11hatj+13hatk`

D

`8hati+8hatj+8hatk`

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The correct Answer is:
To find the position vector of point D in the parallelogram ABCD, we can use the properties of vectors in a parallelogram. The position vectors of points A, B, and C are given as follows: - Position vector of A: \( \vec{A} = \hat{i} + 3\hat{j} + 5\hat{k} \) - Position vector of B: \( \vec{B} = \hat{i} + \hat{j} + \hat{k} \) - Position vector of C: \( \vec{C} = 7\hat{i} + 7\hat{j} + 7\hat{k} \) Let the position vector of point D be \( \vec{D} = x\hat{i} + y\hat{j} + z\hat{k} \). ### Step 1: Use the property of the parallelogram In a parallelogram, the vector \( \vec{AB} \) is equal to the vector \( \vec{DC} \). This can be expressed as: \[ \vec{AB} = \vec{B} - \vec{A} = \vec{C} - \vec{D} = \vec{DC} \] ### Step 2: Calculate \( \vec{AB} \) Now, we calculate \( \vec{AB} \): \[ \vec{AB} = \vec{B} - \vec{A} = (\hat{i} + \hat{j} + \hat{k}) - (\hat{i} + 3\hat{j} + 5\hat{k}) \] \[ = \hat{i} + \hat{j} + \hat{k} - \hat{i} - 3\hat{j} - 5\hat{k} \] \[ = 0\hat{i} - 2\hat{j} - 4\hat{k} \] \[ = -2\hat{j} - 4\hat{k} \] ### Step 3: Set up the equation for \( \vec{DC} \) Now, we can express \( \vec{DC} \): \[ \vec{DC} = \vec{C} - \vec{D} = (7\hat{i} + 7\hat{j} + 7\hat{k}) - (x\hat{i} + y\hat{j} + z\hat{k}) \] \[ = (7 - x)\hat{i} + (7 - y)\hat{j} + (7 - z)\hat{k} \] ### Step 4: Set \( \vec{AB} = \vec{DC} \) Since \( \vec{AB} = \vec{DC} \), we can equate the two expressions: \[ 0\hat{i} - 2\hat{j} - 4\hat{k} = (7 - x)\hat{i} + (7 - y)\hat{j} + (7 - z)\hat{k} \] ### Step 5: Compare coefficients From the equation above, we can compare the coefficients of \( \hat{i} \), \( \hat{j} \), and \( \hat{k} \): 1. For \( \hat{i} \): \[ 0 = 7 - x \implies x = 7 \] 2. For \( \hat{j} \): \[ -2 = 7 - y \implies y = 9 \] 3. For \( \hat{k} \): \[ -4 = 7 - z \implies z = 11 \] ### Step 6: Write the position vector of D Now, substituting the values of \( x \), \( y \), and \( z \) back into the position vector of D: \[ \vec{D} = 7\hat{i} + 9\hat{j} + 11\hat{k} \] ### Final Answer The position vector of point D is: \[ \vec{D} = 7\hat{i} + 9\hat{j} + 11\hat{k} \]

To find the position vector of point D in the parallelogram ABCD, we can use the properties of vectors in a parallelogram. The position vectors of points A, B, and C are given as follows: - Position vector of A: \( \vec{A} = \hat{i} + 3\hat{j} + 5\hat{k} \) - Position vector of B: \( \vec{B} = \hat{i} + \hat{j} + \hat{k} \) - Position vector of C: \( \vec{C} = 7\hat{i} + 7\hat{j} + 7\hat{k} \) Let the position vector of point D be \( \vec{D} = x\hat{i} + y\hat{j} + z\hat{k} \). ...
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