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In a regular hexagon ABCDEF, vecAB=a, ve...

In a regular hexagon ABCDEF, `vecAB=a, vecBC=b and vecCD = c. Then, vecAE =`

A

`2b-a`

B

`b-a`

C

`2a-b`

D

`a+b`

Text Solution

Verified by Experts

The correct Answer is:
A
As in figure, `AB=a,BC=b`,
So, `AD=2b and ED=a`

Now, `AE+ED=AD`
`impliesAE=AD-ED=2b-a`
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