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A,B,C and D have position vectors a,b,c ...

A,B,C and D have position vectors a,b,c and d, respectively, such that a-b=2(d-c). Then,

A

AB and CD bisect each other

B

BD and AC bisect each other

C

AB and CD trisect each other

D

BD and AC trisect each other

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The correct Answer is:
D

`a-b=2(d-c)`
`therefore(a+2c)/(2+1)=(b+2d)/(2+1)`
Hence, AC and BD trisect each other as LHS is the position vector of a point trisecting A an C, and RHS that of B and D.
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