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If a+b is along the angle bisector of a ...

If a+b is along the angle bisector of a and b, where `|a|=lamda|b|`, then the number of digits in value of `lamda` is

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The correct Answer is:
1

Since, angle bisector of a and b
`impliesh(hata+hatb)=h((a)/(|a|)+(b)/(|b|))` . . . (i)
Given, a+b is alongg angle bisector
`implies mu((a)/(|a|)+(b)/(|b|))=a+b`
only, when `|a|=|b|=mu`
`therefore|a|=|b| implies lamda=1`.
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