A sample of `U^(238) ("half life" = 4.5 xx 10^(9)yr)` ore is found to contain `23.8 g" of " U^(238) ` and `20.6g ` of `Pb^(206)`. Calculate the age of the ore

A sample of U^(238) (half-line = 4.5xx10^(9) yr ) ore is found to contain 23.8g of U^(238) and 20.6g of Pb^(206) Calculate the age of the ore.

A sample of U^(238) (t_(1//2)= 4.5 xx 10^(9) yrs) is found to contains 23.8g U^(238) and 20.6g Pb^(206) , the age of ore is

Uranium ._(92)U^(238) decayed to ._(82)Pb^(206) . They decay process is ._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206)) t_(1//2) of U^(238) = 4.5 xx 10^(9) years A sample of rock south America contains equal number of atoms of U^(238) and Pb^(206) . The age of rock will be

Initially the earth was a fire-ball, slowly it has cooled to form earth crust and its different layers. At the beginning ""_(92)^(238)U was present and no ""_(82)^(206) Pb was there. With the passage of time, uranium decayed to ""_(82)^(206)Pb The decay process is : ""_(92)^(238)U underset((x alpha, y beta))to ""_(82)^(206)Pb , t_(1//2) of ""^(238)U = 4.5 xx 10^(9) yrs A sample of rock from south America contains equal number of atoms of ""^(238)U and ""^(206)Pb . The age of the rock will be :