The number of moles of `KMnO_(4)` required to oxidise `1 mol` of `Fe(C_(2)O_(4))` in acidic medium is

Options

A. `0.6`
B. `1.67`
C. `0.2`
D. `0.4`

Answer

A

Explanation

`underset((n=5))("Equivalent of "MnO_(4)^(ө)) = underset((n=3))("Equivalent of "Fe(C_(2)O_(4)))`
`(1)/(5) mol =(1)/(3) mol`
`(3)/(5)"mol of" MnO_(4)^(ө) = 1 "mol of" Fe(C_(2)O_(4))`
`0.6 "mol of" MnO_(4)^(ө) = 1 mol Fe (C_(2)O_(4))`