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aK(2)Cr(2)O(7)+bKCl+cH(2)SO(4)rarrxCrO(2...

`aK_(2)Cr_(2)O_(7)+bKCl+cH_(2)SO_(4)rarrxCrO_(2)Cl_(2)+yKHSO_(4)+zH_(2)O`
The above equation balances when

A

`a=2, b=4,c=6 and x=2, y=6, z=3`

B

`a=4, b=2,c=6 and x=6,y=2,z=3`

C

`a=6,b=4,c=2 and x=6,y=3,z=2`

D

`a=1,b=4,c=6 and x=2,y=6,z=3`

Text Solution

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The correct Answer is:
To balance the given chemical equation: \[ aK_2Cr_2O_7 + bKCl + cH_2SO_4 \rightarrow xCrO_2Cl_2 + yKHSO_4 + zH_2O \] we need to determine the coefficients \( a, b, c, x, y, z \) such that the number of atoms of each element is equal on both sides of the equation. ### Step 1: Identify the number of atoms for each element in the reactants and products. **Reactants:** - Potassium (K): \( 2a + b \) - Chromium (Cr): \( 2a \) - Oxygen (O): \( 7a \) - Chlorine (Cl): \( b \) - Hydrogen (H): \( 2c \) - Sulfur (S): \( c \) **Products:** - Potassium (K): \( y \) - Chromium (Cr): \( x \) - Oxygen (O): \( 2x + 4y + z \) - Chlorine (Cl): \( 2x \) - Hydrogen (H): \( y + 2z \) - Sulfur (S): \( y \) ### Step 2: Set up equations based on the conservation of atoms. 1. **For Potassium (K):** \[ 2a + b = y \quad \text{(1)} \] 2. **For Chromium (Cr):** \[ 2a = x \quad \text{(2)} \] 3. **For Oxygen (O):** \[ 7a + 4c = 2x + 4y + z \quad \text{(3)} \] 4. **For Chlorine (Cl):** \[ b = 2x \quad \text{(4)} \] 5. **For Hydrogen (H):** \[ 2c = y + 2z \quad \text{(5)} \] 6. **For Sulfur (S):** \[ c = y \quad \text{(6)} \] ### Step 3: Solve the equations. From equation (2): \[ x = 2a \] From equation (4): \[ b = 2(2a) = 4a \] From equation (6): \[ c = y \] Substituting \( c \) in equation (5): \[ 2y = y + 2z \implies y = 2z \quad \text{(7)} \] Now substitute \( b \) and \( c \) into equation (1): \[ 2a + 4a = y \implies 6a = y \] Substituting \( y \) from equation (7): \[ 6a = 2z \implies z = 3a \] Now we have: - \( x = 2a \) - \( b = 4a \) - \( c = 6a \) - \( y = 6a \) - \( z = 3a \) ### Step 4: Choose a value for \( a \). Let’s set \( a = 1 \): - \( x = 2(1) = 2 \) - \( b = 4(1) = 4 \) - \( c = 6(1) = 6 \) - \( y = 6(1) = 6 \) - \( z = 3(1) = 3 \) ### Final Balanced Equation: The balanced equation is: \[ 1K_2Cr_2O_7 + 4KCl + 6H_2SO_4 \rightarrow 2CrO_2Cl_2 + 6KHSO_4 + 3H_2O \] ### Summary of Coefficients: - \( a = 1 \) - \( b = 4 \) - \( c = 6 \) - \( x = 2 \) - \( y = 6 \) - \( z = 3 \)

To balance the given chemical equation: \[ aK_2Cr_2O_7 + bKCl + cH_2SO_4 \rightarrow xCrO_2Cl_2 + yKHSO_4 + zH_2O \] we need to determine the coefficients \( a, b, c, x, y, z \) such that the number of atoms of each element is equal on both sides of the equation. ### Step 1: Identify the number of atoms for each element in the reactants and products. ...
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  12. Which of the following is not an intramolecular redox reaction?

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  16. The number of electrons lost in the following change is Fe+H(2)Orarr...

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  17. The oxidation number of Pt in [Pt (C(2)H(4))Cl(3))"]"^(ө) is

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  18. The oxidation number of P in Mg(2)P(2)O(7) is

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