In alkaline medium, `ClO_(2)` oxidises `H_(2)O_(2) "to" O_(2)` and is itself reduced to `Cl^(ө)`. How many moles of `H_(2)O_(2)` are oxidised by `1 "mol of " ClO_(2)` ?

Options

A. 1
B. `3//2`
C. `5//2`
D. `7//2`

Answer

C

Explanation

`5e^(-)+ClO_(2)rarrCl^(ө)`
`underset((n=5))("Eq of"ClO_(2))=underset((n=2))("Eq of" H_(2)O_(2))`
`(1)/(5)"mol"-=(1)/(2)"mol"`
`1 "mol of "ClO_(2)=(5)/(2)"mol of"H_(2)O_(2)`