Calculate
a. The number of electrons which will together weight i.g.
b. The mass of `1` mol of electron
c. The charge of `1` mol of electrons

Explanation

`9.1 xx 10^(-20) g ` is the mass of `1` electron
`1g ` is the mass of `(1 xx 1)/(9.12 xx 10^(-20)) = 1.09 xx 10^(23)` electron
b. `1` mol of electron `= 6.02 xx 10^(22)`
Mass of `1` electron `= 9.1 xx 10^(-28)g`
Mass of `6.02 xx 10^(23)` electron
`= 6.02 xx 10^(23) xx 9.1 xx 10^(-20) = 5.478 xx 10^(-4) g`
c. `1` mol of electron `= 6.02 xx 10^(23) ` electron
Change of electron `= 1.60 xx 10^(-19) C`
Change of `6.02 xx 10^(28) `electron
`= 1.60 xx 10^(-19) xx 6.02 xx 16^(Theta) C = 9.632 xx 10^(6)C`