Calculate the longest wavelength that can an electron from the first bohr given `E_(1) = 13.6 eV`

Explanation

The photon capable of removing an electron from the first bohr orbit posses energy `= 13.6eV`
`= 13.6 xx 1.602 xx 10^(-19) J`
`= 21.787 xx 10^(-19) J`
`," E = (hc)/(lambda)`
`21.787 xx 10^(-19) = (6.625 xx 10^(-34) xx 3.0 xx 10^(8))/(lambda)`
`:. lambda = 912.24 xx 10^(-10)m = 912.24 Å`
Energy of photon `E = Nhv = (Nhv)/(lambda)`
:. Number of photon electrons emitted per minut
`(N) = (E lambda)/(hc)`
`= (6000 J xx 300 xx 10^(-9)m)/(6.626 xx 10^(-34) J s xx 3 xx 10^(8) ms^(-1))`
`= 9.05 xx 10^(22)`photons