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The dissociation energy of H(2) is 430.5...

The dissociation energy of `H_(2)` is `430.53 kJ mol^(-1), `If `H_(2)` is of disociated by illamition wityh radiation of wavelength `253.7 nm` , the fraction of the radiant energy which will be converted into ikinetic energy is given by

A

`8.56 %`

B

`2.33 %`

C

`1.3%`

D

`90%~

Text Solution

Verified by Experts

`(hc)/(lambda) = (430.53 xx 10^(3))/(6.023 xx 10^(23)) + KE`
`KE = (6.626 xx 10^(-34) xx 3 xx 10^(8))/(253.7 xx 10^(-9))`
`= (430.53 xx 10^(3))/(6.023 xx 10^(23)) = 6.9 xx 10^(-20)`
`:. Frection = (6.9 xx 10^(-20))/(7.83 xx 10^(-19)) = 0.088 = 8.86`
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