An iodine dissociates into atom after absorting light of wave length `4500Å` If quantum of radition is absorbed by each molecule calculate the kinetic energy of iodine (Bood energy of `I_(2) is 240 kJ`(mol))

Explanation

Energy gives to iodine molecule
`(hc)/(lambda) = (6.625 xx 10^(-34) xx 3 xx 10^(8))/(4500 xx 10^(-10))`
`4.417 xx 10^(-19) J`
Energy used for breaking up `I_(2)` moleculem is
` = (240 xx 10^(5))/(6.025 xx 10^(23)) = 3.894 xx 10^(-19) J`
Therefore energy used in impairting kinetic energy to two atoms is
`(4.417 - 3.984) xx 10^(-19) J`
KE of iodine atom `= ((4.417 - 3.489))/(2) xx 10^(-19)`
`= 0.216 xx 10^(-19) J`