A dye obsorbs light of `lambda = 4530 Å` and then flaorescences light of `5000Å` .Assuming that uinder given condition `47%` of the obserbed energy is re-emited out so flaurescence , calculate the ratio of quants emitted out to the number of quanta obserbed

Explanation

WE know energy of light obserbed in one photon
`= (hc)/(lambda_("obserbed"))`
Let `n_(1)` photon be obserbed .Therefore
Total energy obserbed `= (n_(1)hc)/(lambda"obserbed" )`
Now energy of light re-emited then,
Total energy re-emited out `= n_(2) xx (hc)/(lambda_("obserbed"))`
As given `E_("Absorbed") xx (47)/(100) = E_("Re-emmited out" )`
`(lambda c )/(lambda_("Absorbed")) xx n_(1) xx (47)/(100) xx (lambda_("Emitted"))/(lambda_("Absorbed"))`
`(n_(2))/(n_(1)) = (47)/(100) xx (5080)/(4530) = 0.527`