What will be the kinetic energy and total eknergy charge of an in H atom if the atom emit a photon of wavelength `4860 Å`?

Explanation

The energy released is
`E = (hc)/(lambda) = ((6.625 xx 10^(-34) Js) xx ( 3 xx 10^(8) ms^(-1)))/((4860 xx 10^(-10)m))`
`= 4.09 xx 10^(-19) J`
1:. Total energy charge `= 4.09 xx 10^(-19) J`
:. Total energy due to released of photon = gain in kinetic energy `= 4.09 xx 10^(-19) J`