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Calculate the wavelength of the first l...

Calculate the wavelength of the first line in the balmer series of hydrogen spectrum

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To calculate the wavelength of the first line in the Balmer series of the hydrogen spectrum, we can use the Rydberg formula for hydrogen: \[ \frac{1}{\lambda} = R_H \cdot Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right) \] Where: - \( \lambda \) is the wavelength, ...
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Knowledge Check

  • The wavelength of the third line of the Balmer series for a hydrogen atom is -

    A
    `(21)/(100R_(H))`
    B
    `(100)/(21 R_(H))`
    C
    `(21R_(H))/(100)`
    D
    `(100R_(H))/(21)`

  • If the wavelength of the first line of the Balmer series of hydrogen is 6561 A, the wavelength of the second line of the series should be.

    A
    `13122 Å`
    B
    `3280Å`
    C
    `4860Å`
    D
    `2178Å`

  • The wavelength of the first spectral line of the Lyman series of hydrogen spectrum is

    A
    912 Å
    B
    1215 Å
    C
    1512 Å
    D
    6563 Å

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    If the wavelength of the first line of the Balmer series of hydrogen is 6561 Å , the wavelngth of the second line of the series should be

    If the wavelength of the first line of the Balmer series of hydrogen atom is 656.1 nm the wavelngth of the second line of this series would be

    The wave number of the H_(a)- line in Balmer series of hydrogen spectrum is

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