The shortest wavelength in `H` spectrum of Lyman series when `R_(H) = 109678 cm^(-1)` is

Options

A. `1002.7 Å`
B. `1215.67 Å`
C. `1127.30Å`
D. `911.7 Å`

Answer

D

Explanation

For Lyman series `n_(1) = 1`
For shortest 'wavelength ' of Lyman series the energy difference in two level showing transition should be maximum (i.e, `n_(2) = oo)`
`(1)/(lambda) = R_(H) = [(1)/(1^(2)) - (1)/(oo^(2))] = lambda = (1)/(10678)`
`= 109678 rArr lambda = (1)/(10678)= 911.7 xx 10^(-8) = 911.7 Å`