A spectral line in the spectrum of H atom has a wavelength of `15222.22 cm^(-1)` .The transition responsible for this rediation is (Rydherg constant `R = 10977 cm^(-1)`

Options

A. `2 rarr 1`
B. `4 rarr 2`
C. `5 rarr 2`
D. `2 rarr 3`

Explanation

`lambda = (1)/(bar v) = (1)/(15222.32) = 6.569 xx 10^(-5)cm = 6569 Å`(Visible light wavelength)
Clearly it lies in the visible regain i.e. in balmer series Hence `n_(1) = 2` Using the relation for wavelength foir H atom
`bar v = (1)/(lambda) = RZ^(2)((1)/(n_(1)^(2))- (1)/(n_(2)^(2)))`
`15222.22=109677(1/2^(2)-1/n_(2)^(2))`
`n_(1) = 3`
THe required transition is `3 rarr 2` gtHence c is correct