Calculate the wavelength of the first line in the series limit for the Lyman series for hydrogen

Explanation

For the first line
`(1)/(lambda) = 109678 ((1)/(1^(2)) - (1)/(2^(2))) = 82259 cm^(-1)`
`lambda = 1.21517 xx 10^(-5) cm `
For the series limit
`(1)/(lambda) = 109678((1)/(1^(2))- (1)/(oo))`
`= 109678((1)/(1) - 0)= 109678 cm^(-1)`
` lambda = 9.1176 xx 10^(-6) cm`