A photon of `3000 Å` is obserbed by a gas and then re-emmited as two photon .One photon in red (`7600 Å)` what would be the wavelength of the other photon ?

Explanation

`hv = hv_(1) + hv_(2)`
`or (hv)/(lambda) = (hv)/(lambda_(1)) + (hv)/(lambda_(2))`
`or (1)/(3000) = (1)/(7600) + (1)/(lambda_(2))`
`or (1)/(3000) = (1)/(7600) + (1)/(lambda_(2))`
`or lambda_(2) = (228000)/(46) = 4956.5 Å`