The energy required in ionise a helium atom is equal to `24.6 eV` The energy required to remove both the electron from the helium atom would be

Options

A. `59 eV`0
B. `81 eV`
C. `79 eV`
D. `40 eV`

Explanation

`He rarr He^(o+) + e IP_(1) = 24.6 eV`
`He^(o+) rarr He^(2+) + e IP_(2) =`?
` IP_(2) =13.6 eVxx Z^(2) = 13.6 eVxx Z^(2) = 54.4 eV`
` IP_(1) + IP_(2) = 24.6 + 54.4 = 79 eV`