The circumference of the first Bohr orbit in H atom is `3.322 xx 10^(-10) m` .What of the electron of this orbit ?

Explanation

According to Bohr's model
`mvr = (nh)/(2pi) `,Given `n = 1` and `2pir` (circumference)
`= 3.322 xx 10^(-10)m`
`v = (nh)/(2pi mr) = (1 xx (6.626 xx 10^(-34) J s))/((9.1 xx 10^(-31) kg) xx 3.322 xx 10^(-10)m)`
`2.19 xx 10^(6) ms^(-1)`