Calculate the particle of the uncertainty of the displacement and velocity of a electron having mass `9.1 xx 10^(-28) g`

Explanation

According to Heisenberg uncertainty principle
`Delta x - Delta p = (h)/(4pi)`
`or Delta x - m Delta v =(h)/(4pi)`
`:. Delta x - Delta v=(h)/(4pi xxm)=(6.6 xx 10^(-34) kg m^(2)s^(-1))/(4 xx3.14 xx 9.1 xx 10^(-31) kg)`
`= Delta x - Delta v= 5.8 xx 10^(-5) m^(2)s^(-1) `
The product of uncertainty is `5.8 xx 10^(-5) m^(2)s^(-1)`