What is the total number of part of electron at lead three same quantum number of Be ?

Explanation

`Be(Z= 4)`
Electric configuration is `1s^(2)2s^(2)`
For s electron the quantum number are
`n = 1,l= 0,m = 0 ,s= (1)/(2)`…..(i)
`n = 1,l= 0,m = 0 ,s=- (1)/(2)`.....(ii)brgt `n = 2,l= 0,m = 0 ,s= (1)/(2)`.....(iii)
`n = 2,l= 0,m = 0 ,s=- (1)/(2)`.....(iv)
Clearly there are the position graps (i) and (ii) ,(iii) and (iv),(i) and (iii) and (ii) and (iv)