Which among the following electron will emit radiation of maximum wavelength ?

Options

A. `n= 4,l= 1,m= 0 "to" n= 3,l= 2,m= -2`
B. `n= 3,l= 2,,m= -2 "to" n= 3,l= 1,m= -1`
C. `n= 3,l= 2,,m= 1 "to" n= 2,l= 0,m= 0`
D. `n= 3,l= 1,,m= 0 "to" n= 2,l= 1,m= 1`

Explanation

for `lambda_("max") E_("radent") = maximum = 13.6Z^(2)((1)/(n_(1)^(2)) - (1)/(n_(2)^(2)))i.e.`
`((1)/(n_(1)^(2)) - (1)/n_(2)^(2))` has to be minimum
This is independent of quantum number l,m and s Chearty `n_(1) = 3` and `n_(2) = 4` minimum E radiation