Calculate the total spin and magnitic moment for atom having atomic number `7,24,34 and 36`

Explanation

The electron configuration are as follows
`7N : 1s^(2) 2s^(2) 2p^(3)` Unpaired electron = 3
`._(29) Cr : 1s^(2)2s^(2)2p^(3) 3s^(2)3p^(6) 3d^(5) 4s^(1)` Unpaired electron `= 6`
`._(34) Se : 1s^(2)2s^(2)2p^(6) 3s^(2)3p^(6) 3d^(10) 4s^(2)4p^(4)`
Unpaired electron `= 2`
`._(36) Kr : 1s^(2)2s^(2)2p^(6) 3s^(2)3p^(6) 3d^(10) 4s^(2)4p^(6)`
Unpaired electron `= 2`
:. Total spin for an atom `= +- (1)/(2) xx ` Number of upaired electron
For `._(7)N` , it is `+- (3)/(2)` For `_(34)Se `, it is `+- 3`
For `_(36)Kr `, it is `+- 1`, For `._(36)Kt `, it is `0`
Also magnetic moment `= sqrt(n(n + 2))`
For `._(7)N `, it is `sqrt(15)`, For `._(24)Cr `, it is `sqrt(24)`
For `._(34)Se `, it is `sqrt(8)`, For `_(36)Kt `, it is `sqrt(0)`