The quantum number of the last electron of an element are below pralict the atomic number and same of the electron from the following quantum number

Explanation

The give quantum number are as fololows
Principal quantum number `(n) = 3`
Azimuthal quantum number `(i) = 2` or `d`
Magnitic number `(m) = 0`

Spin quantum number `(m_(s)) = -(1)/(2)`
Therefore total number of electron in d orbital is `8` Hence it is `d^(9)` configuration it shows that the element is `Ni(3d^(8))`