A neutral atom of an element has `2K,KL ,9M,`and `2N` electon .Find and the following
a. Atomic number
b. Total number of s electron
c Total number of p electron
d.Total number of d electron
e.Velocity of the element
f.Number of unpaired electrons

Explanation

Electronic configuration of the neutral atom :
`(1s^(2))/(K) ,(2s^(2)2p^(6))/(L),(3s^(2)3p^(6)3d^(1))/(M) ,(4s^(2))/(N)`
a. Atomic number = Total number of electrons in neutrual atom `= 21`
b.Total number of s electrons `= 8`
c.Total number of p electrons `= 12`
d. Total number of d electron `= 1`
e. VAlency of element `= + 2 and + 3`
(due to number of electrons in outer shell and penadimate d sub-shell)
f. Number of unpaired electrons `= 1 (of 3d)`