Calculate the wavelength of radiation emitted producing a line in the Lyman series ,when as electron falls dfrom fourth stationary in hydrogen atom `(R_(H) = 1.1 xx 10^(7)m^(-1)`

Explanation

`(1)/(lambda) = R_(H) [(1)/(n_(1)^(2)) - (1)/(n_(2)^(2))]`
Given `R_(H) = 1.1 xx 10^(7)` for Lyman series `n_(1) = 1 `and `n_(2) = 4` (gives ) Therefore
`(1)/(lambda) =1.1 xx 10^(7)[(1)/(1^(2)) - (1)/(4^(2))]`
`lambda= 0.9696 xx 10^(-7) m)`