The binding energy of electron in a metal is `193 kJ mol^(-1)` .Find the threshold frequancy of the metal

Answer

A, C, D

Explanation

E(binding energy per atom) `= (193 xx 10^(3) J mol ^(-1))/(6.023 xx 10^(23) mol^(-1))`
`= 3.20 xx 10^(-19) J" atom"^(-1)`
Threshold frequency of the metal
`v = (E)/(h) = (3.20 xx 10^(-19) J )/(6.626 xx 10^(-34) J s)- 4.83 xx 10^(14) s^(-1)`