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Calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom

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To calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom, we can use the formula given by Bohr's model of the atom. The formula for the velocity (v) of an electron in the nth orbit is: \[ v = \frac{2.18 \times 10^6 \times z}{n} \] Where: - \( z \) is the atomic number of the element (for hydrogen, \( z = 1 \)) - \( n \) is the principal quantum number (for the first orbit, \( n = 1 \)) ### Step-by-Step Solution: 1. **Identify the values of z and n:** - For hydrogen, the atomic number \( z = 1 \). - For the first orbit, the principal quantum number \( n = 1 \). 2. **Substitute the values into the formula:** \[ v = \frac{2.18 \times 10^6 \times 1}{1} \] 3. **Calculate the velocity:** \[ v = 2.18 \times 10^6 \text{ m/s} \] Thus, the velocity of the electron in the first Bohr orbit of a hydrogen atom is \( 2.18 \times 10^6 \) m/s.

To calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom, we can use the formula given by Bohr's model of the atom. The formula for the velocity (v) of an electron in the nth orbit is: \[ v = \frac{2.18 \times 10^6 \times z}{n} \] Where: - \( z \) is the atomic number of the element (for hydrogen, \( z = 1 \)) - \( n \) is the principal quantum number (for the first orbit, \( n = 1 \)) ...
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Calculate the velocity of an electron in the first Borh's orbit of hydrogen atom (given r = a_(0)) b. Find de Broglie wavelength of the electron in the first Bohr's orbit c. Find the orbital angular momentum of 2p orbital in terms of h//2pi units

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Knowledge Check

  • The energy of an electron in the nth Bohr orbit of hydrogen atom is

    A
    `-(13.6)/(n^(4))`eV
    B
    `-(13.6)/(n^(3))`eV
    C
    `-(13.6)/(n^(2)) ` eV
    D
    `-(13.6)/(n) ` eV
  • The velocity of an electron in the first Bohr orbit of hydrogen atom is 2.19 xx 10^(6)ms^(-1) . Its velocity in the second orbit would be

    A
    `1.10 xx 10^(6)ms^(-1)`
    B
    `4.38 xx 10^(6)ms^(-1)`
    C
    `5.5 xx 10^(5)ms^(-1)`
    D
    `8.76 xx 10^(6)ms^(-1)`
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