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Calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom

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To calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom, we can use the formula given by Bohr's model of the atom. The formula for the velocity (v) of an electron in the nth orbit is: \[ v = \frac{2.18 \times 10^6 \times z}{n} \] Where: - \( z \) is the atomic number of the element (for hydrogen, \( z = 1 \)) - \( n \) is the principal quantum number (for the first orbit, \( n = 1 \)) ### Step-by-Step Solution: 1. **Identify the values of z and n:** - For hydrogen, the atomic number \( z = 1 \). - For the first orbit, the principal quantum number \( n = 1 \). 2. **Substitute the values into the formula:** \[ v = \frac{2.18 \times 10^6 \times 1}{1} \] 3. **Calculate the velocity:** \[ v = 2.18 \times 10^6 \text{ m/s} \] Thus, the velocity of the electron in the first Bohr orbit of a hydrogen atom is \( 2.18 \times 10^6 \) m/s.

To calculate the velocity of an electron in the first Bohr orbit of a hydrogen atom, we can use the formula given by Bohr's model of the atom. The formula for the velocity (v) of an electron in the nth orbit is: \[ v = \frac{2.18 \times 10^6 \times z}{n} \] Where: - \( z \) is the atomic number of the element (for hydrogen, \( z = 1 \)) - \( n \) is the principal quantum number (for the first orbit, \( n = 1 \)) ...
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