Calculate the wavelength and energy for radiation emitted for the electron transition from infinite `(oo)` to stationary state of the hydrogen atom
`R = 1.0967 xx 10^(7) m^(-1), h = 6.6256 xx 10^(-34) J s ` and `c = 2.979 xx 10^(8) m s^(-1)`

Answer

A, B, C, D

Explanation

`n_(1) = 1,n_(2) = oo,(1)/(lambda) = 1.09678 xx 10^(7) [(1)/(1^(2)) - (1)/(oo^(2))]`
`lambda = 9.11 xx 10^(6) m `
`lambda = 9.11 xx 10^(-6) m`
`E = hv = b(c )/(lambda) = Rhc (since (1)/(lambda) = R)`
` = 1.09678 xx 10^(7) xx 6.62 xx 10^(-34) xx 3 xx 10^(8) m`
`= 217.9 xx 10^(-20) J`
`217.9 xx 10^(-23) kJ`