An electron in H-atom in its ground state absorbs ` 1.5` times as much energy as the minimum required for its escape ( i. e., 13 . 6 eV) from the atom . Calculate the wavelength of emitted electron.

Answer

A, B, D

Explanation

IE of H atom = `13.6 eV`
Incident energy `= 1.5 xx IE = 1.5 xx 13.6 eV`
KE of e' ejected out `= 1.5 xx 13.6 - 13.6 = 0.5 xx 13.6`
`E_(k) = 0.5 xx 13.6 eV = 6.8 xx 1.6 xx 10^(-19) J`
`lambda = (h)/(sqrt(2Em)) = (6.62 xx 10^(-34) J s)/(( 2 xx 6.8 xx 9.1 xx 10^(-31) kg xx 1.6 xx 10^(-19))^(1//2))`
`= (6.62 xx 10^(-9))/(14.07)`
`lambda = 4.71 Å`