What is the final velocity of an electron accelerating through a potential of `1600 V` if its initial velocity is zero .

Answer

A, B, C

Explanation

`(1)/(2) mv^(2) = eV`
`v = sqrt((2eV)/(m)) = [(2 xx 1.6 xx 10^(34) xx 1600)/(9.1 xx 10^(-31))] `
`= 2.37 xx 10^(7) m s^(-1)`