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An nodel of N has vapour density 46 fin...

An nodel of N has vapour density `46` find the total number of electron in its `92 g.(N_(A) = ` Avogdro's number )

A

`46N_(A)`

B

`38N_(A)`

C

`54N_(A)`

D

`30N_(A)`

Text Solution

Verified by Experts

The correct Answer is:
A
Vapour density `= 46`
Molecular weight `= 92`
So compound is `N_(2)O_(4)`
Total number `e = 7 xx 2 + 8 xx 4 = 46`
Total number of `e^(-)` in `1` mole `= 46N_(A)`
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